From 6ebdfb6be7eb1762a1a97e8cf1fb485247da42fa Mon Sep 17 00:00:00 2001 From: Yinghai Lu Date: Mon, 27 Jan 2014 17:06:52 -0800 Subject: [PATCH] memblock: don't silently align size in memblock_virt_alloc() In original __alloc_memory_core_early() for bootmem wrapper, we do not align size silently. We should not do that, as later free with old size will leave some range not freed. It's obvious that code is copied from memblock_base_nid(), and that code is wrong for the same reason. Also remove that in memblock_alloc_base. Signed-off-by: Yinghai Lu Acked-by: Santosh Shilimkar Cc: Dave Hansen Cc: Russell King Cc: Konrad Rzeszutek Wilk Cc: Ingo Molnar Cc: "H. Peter Anvin" Signed-off-by: Andrew Morton Signed-off-by: Linus Torvalds --- mm/memblock.c | 6 ------ 1 file changed, 6 deletions(-) diff --git a/mm/memblock.c b/mm/memblock.c index 9c0aeef194404..87d21a6ff63c5 100644 --- a/mm/memblock.c +++ b/mm/memblock.c @@ -984,9 +984,6 @@ static phys_addr_t __init memblock_alloc_base_nid(phys_addr_t size, if (!align) align = SMP_CACHE_BYTES; - /* align @size to avoid excessive fragmentation on reserved array */ - size = round_up(size, align); - found = memblock_find_in_range_node(size, align, 0, max_addr, nid); if (found && !memblock_reserve(found, size)) return found; @@ -1080,9 +1077,6 @@ static void * __init memblock_virt_alloc_internal( if (!align) align = SMP_CACHE_BYTES; - /* align @size to avoid excessive fragmentation on reserved array */ - size = round_up(size, align); - again: alloc = memblock_find_in_range_node(size, align, min_addr, max_addr, nid); -- 2.39.5