One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
size = sizeof(struct foo) + count * sizeof(struct boo);
instance = alloc(size, GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
size = struct_size(instance, entry, count);
This code was detected with the help of Coccinelle.
Signed-off-by: "Gustavo A. R. Silva" <gustavo@embeddedor.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
u16 i, num_groups_added = 0;
enum ice_status status = 0;
struct ice_hw *hw = pi->hw;
- u16 buf_size;
+ size_t buf_size;
u32 teid;
- buf_size = sizeof(*buf) + sizeof(*buf->generic) * (num_nodes - 1);
+ buf_size = struct_size(buf, generic, num_nodes - 1);
buf = devm_kzalloc(ice_hw_to_dev(hw), buf_size, GFP_KERNEL);
if (!buf)
return ICE_ERR_NO_MEMORY;