ALSA: seq: Fix race of snd_seq_timer_open()

The timer instance per queue is exclusive, and snd_seq_timer_open()
should have managed the concurrent accesses.  It looks as if it's
checking the already existing timer instance at the beginning, but
it's not right, because there is no protection, hence any later
concurrent call of snd_seq_timer_open() may override the timer
instance easily.  This may result in UAF, as the leftover timer
instance can keep running while the queue itself gets closed, as
spotted by syzkaller recently.

For avoiding the race, add a proper check at the assignment of
tmr->timeri again, and return -EBUSY if it's been already registered.

Reported-by: syzbot+ddc1260a83ed1cbf6fb5@syzkaller.appspotmail.com
Cc: <stable@vger.kernel.org>
Link: https://lore.kernel.org/r/000000000000dce34f05c42f110c@google.com
Link: https://lore.kernel.org/r/20210610152059.24633-1-tiwai@suse.de
Signed-off-by: Takashi Iwai <tiwai@suse.de>

diff --git a/sound/core/seq/seq_timer.c b/sound/core/seq/seq_timer.c
index 1645e4142e30246dc30af69857d1dc8e9f736219..9863be6fd43e1a34aece5ffe258ffc627eb05bc2 100644 (file)
--- a/sound/core/seq/seq_timer.c
+++ b/sound/core/seq/seq_timer.c
@@ -297,8 +297,16 @@ int snd_seq_timer_open(struct snd_seq_queue *q)
                return err;
        }
        spin_lock_irq(&tmr->lock);
-       tmr->timeri = t;
+       if (tmr->timeri)
+               err = -EBUSY;
+       else
+               tmr->timeri = t;
        spin_unlock_irq(&tmr->lock);
+       if (err < 0) {
+               snd_timer_close(t);
+               snd_timer_instance_free(t);
+               return err;
+       }
        return 0;
 }