btrfs: return block group directly at btrfs_next_block_group()

At btrfs_next_block_group(), we have this long line with two statements:

  cache = btrfs_lookup_first_block_group(...); return cache;

This makes it a bit harder to read due to two statements on the same
line, so change that to directly return the result of the call to
btrfs_lookup_first_block_group().

Reviewed-by: Nikolay Borisov <nborisov@suse.com>
Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>

diff --git a/fs/btrfs/block-group.c b/fs/btrfs/block-group.c
index 2c42ce00b84d4bfe30a7691b3e408f38d97508b1..db112a01d711355e9795b0080ee67c6a40f84e89 100644 (file)
--- a/fs/btrfs/block-group.c
+++ b/fs/btrfs/block-group.c
@@ -271,7 +271,7 @@ struct btrfs_block_group *btrfs_next_block_group(
 
                read_unlock(&fs_info->block_group_cache_lock);
                btrfs_put_block_group(cache);
-               cache = btrfs_lookup_first_block_group(fs_info, next_bytenr); return cache;
+               return btrfs_lookup_first_block_group(fs_info, next_bytenr);
        }
        node = rb_next(&cache->cache_node);
        btrfs_put_block_group(cache);