An interesting observation made with our parallel selftests was that on
our small/single cpu systems we would call kthread_stop() before the
kthreads were spawned. If this happens, the kthread is never run at all;
completely bypassing the test.
A simple yield() from the parent will ensure that all children have the
opportunity to start before we reap them.
Signed-off-by: Chris Wilson <chris@chris-wilson.co.uk>
Cc: Matthew Auld <matthew.auld@intel.com>
Reviewed-by: Matthew Auld <matthew.auld@intel.com>
Link: https://patchwork.freedesktop.org/patch/msgid/20191101084940.31838-1-chris@chris-wilson.co.uk
get_task_struct(data[n].tsk);
}
+ yield(); /* start all threads before we kthread_stop() */
+
for (n = 0; n < count; n++) {
int status;
get_task_struct(tsk[i]);
}
+ yield(); /* start all threads before we kthread_stop() */
+
for (i = 0; i < n_cpus; ++i) {
int status;
get_task_struct(tsk);
}
+ yield(); /* start all threads before we begin */
+
intel_engine_pm_get(engine);
set_bit(I915_RESET_ENGINE + id, >->reset.flags);
do {
get_task_struct(tsk[id]);
}
+ yield(); /* start all threads before we kthread_stop() */
+
count = 0;
for_each_engine(engine, smoke->gt, id) {
int status;
get_task_struct(threads[n]);
}
+ yield(); /* start all threads before we begin */
msleep(jiffies_to_msecs(i915_selftest.timeout_jiffies));
for (n = 0; n < ncpus; n++) {
get_task_struct(tsk[idx++]);
}
+ yield(); /* start all threads before we kthread_stop() */
+
idx = 0;
for_each_uabi_engine(engine, i915) {
int status;
idx++;
}
+ yield(); /* start all threads before we begin */
msleep(jiffies_to_msecs(i915_selftest.timeout_jiffies));
out_flush: