uuid: remove licence boilerplate text from the header

Remove licence boilerplate text from the UAPI header.

Link: https://lkml.kernel.org/r/20211216113552.81199-2-andriy.shevchenko@linux.intel.com
Signed-off-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Acked-by: Christoph Hellwig <hch@lst.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

diff --git a/include/uapi/linux/uuid.h b/include/uapi/linux/uuid.h
index 32615dc5f0cfb95edc4770fee94c593a0c7d76ab..c0f4bd9b040edfef983d2cb8a3e85196eda1e195 100644 (file)
--- a/include/uapi/linux/uuid.h
+++ b/include/uapi/linux/uuid.h
@@ -5,15 +5,6 @@
  *
  * Copyright (C) 2010, Intel Corp.
  *     Huang Ying <ying.huang@intel.com>
- *
- * This program is free software; you can redistribute it and/or
- * modify it under the terms of the GNU General Public License version
- * 2 as published by the Free Software Foundation;
- *
- * This program is distributed in the hope that it will be useful,
- * but WITHOUT ANY WARRANTY; without even the implied warranty of
- * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
- * GNU General Public License for more details.
  */
 
 #ifndef _UAPI_LINUX_UUID_H_